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2a^2-28a=960
We move all terms to the left:
2a^2-28a-(960)=0
a = 2; b = -28; c = -960;
Δ = b2-4ac
Δ = -282-4·2·(-960)
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8464}=92$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-92}{2*2}=\frac{-64}{4} =-16 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+92}{2*2}=\frac{120}{4} =30 $
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